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Question of the Day!
[Appeared XAT 2012]
Topic: Numbers
A potter asked his two sons to sell some pots in the market. The amount received for each pot was same as the number of pots sold. The two brothers spent the entire amount on some packets of potato chips and one packet of banana chips. One brother had the packet of banana chips along with some packets of potato chips, while the other brother just had potato chips. Each packet of potato chips costs 10/- and the packet of banana chips costs less than 10/-. The packets of chips were divided between the two brothers so each brother received equal number of packets. How much money should one brother give to the other to make the division financially equitable?

  1. A 1 10%
  2. B 2 34%
  3. C 4 28%
  4. D 5 22%
  5. E 7 5%
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8 Thanks 99 Attempts 1 Comment
Sanjay Jadhav 10 months ago
2

The numbers from 1 to m are written one after another as follows 1234567&&.m. The resulting number is divisible by 3 if m is of the form (n is a natural number):
I. 3n
II. 3n - 1
III. 3n - 2

  1. A I only 37%
  2. B I and II only 31%
  3. C I and III only 23%
  4. D II and III only 9%
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1 Thanks 81 Attempts 4 Comments
Sanjay Jadhav 10 months ago
B options

Question of the Day!
[Appeared XAT 2008]
Topic: Numbers
A rural child specialist has to determine the weight of five children of different ages. He knows from his past experience that each of the children would weigh less than 30 Kg and each of them would have different weights. Unfortunately, the scale available in the village can measure weight only over 30 Kg. The doctor decides to weigh the children in pairs. However, his new assistant weighed the children without noting down the names. The weights were: 35, 36, 37, 39, 40, 41, 42, 45, 46 and 47 Kg. The weight of the lightest
child is:

  1. A 15 31%
  2. B 16 25%
  3. C 17 29%
  4. D 18 13%
  5. E 20 1%
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5 Thanks 83 Attempts 1 Comment
Shashank Jaiswal 1 year ago
As each child appears for four times in the given ten pairs,

Sum of the weights of the five children = 408 / 4 = 102

Let weight of the lightest child and that of hevaiest child be x

and y

Then the weight of the second lightest child = 35 - x

The weight of the third lightest child = 36 - x

The weight of the second heaviest child = 47 - y

(x + 35 - x + 36 - x + y + 47 - y) = 102

=> x = 16

Question of the Day!
[Appeared CAT 2000]
Topic: Numbers
Let S be the set of prime numbers greater than or equal to 2 and less than 100. Multiply all elements of S. With how many consecutive zeros will the product end?

  1. A 1 74%
  2. B 4 10%
  3. C 5 6%
  4. D 10 9%
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2 Thanks 77 Attempts 1 Comment
Dev 1 year ago
Now how do we get the solution?

Question of the Day!
[Appeared CAT 2004]
Topic: Numbers
Suppose n is an integer such that the sum of digits of n is 2, and 10^10 < n < 10^11. The number of different values of n is

  1. A 11 30%
  2. B 10 43%
  3. C 9 17%
  4. D 8 10%
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2 Thanks 83 Attempts 4 Comments
Sumith Gali 1 year ago
Any queries let me know

Question of the Day!
[Appeared CAT 2002]
Topic: Numbers
Number S is obtained by squaring the sum of digits of a two-digit number D. If difference between S and D is 27, then the two-digit number D is

  1. A 24 13%
  2. B 54 77%
  3. C 34 6%
  4. D 45 4%
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2 Thanks 98 Attempts 1 Comment
MITz 1 year ago
b

Question of the Day!
[Appeared CAT 2001]
Topic: Numbers
In a four-digit number, the sum of the first 2 digits is equal to that of the last 2 digits. The sum of the first and last digits is equal to the third digit. Finally, the sum of the second and fourth digits is twice the sum of the other 2 digits. What is the third digit of the number?

  1. A 5 57%
  2. B 8 22%
  3. C 1 9%
  4. D 4 12%
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3 Thanks 86 Attempts 2 Comments
Ankit Singh 1 year ago
5
Janne Rohith reddy 1 year ago
1565^8-1551^8=(1565^4+1551^4)(1565^2+1551^2)*(1565+1551)*(1565-1551)=(1565^4+1551^4)(1565^2+1551^2)*(1565+1551)*(1565-1551)*14=14x\8=remainder 6
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